BinaryGap My 100% Solution in Javascript

Question

app.codility.com

My Solution

app.codility.com

function solution(N) {
    
    let input = N;
    let count = 0;
    let maxCount = 0;
    let startCount = false;
    
    while (input > 0) {
        let bit = input%2;
        
        if (bit === 0) {
            if (startCount) 
                count++;
        } else {
            startCount = true;
            if (count > maxCount) {
                maxCount = count;
            }
            count = 0;
        }
        
        input = Math.floor(input/2);
    }
    
    return maxCount;
}

Solution Online

www.zsoltnagy.eu

function solution( N ) {
    let str = N.toString( 2 ), 
        zeroCount = 0,
        result = 0;
 
    for ( let digit of str ) {
        if ( digit === '0' ) {
            zeroCount += 1;
        } else /* if ( digit === '1' ) */ {
            result = Math.max( result, zeroCount );
            zeroCount = 0;
        }
    }
 
    return result;
}

Note

• I start from the last bit(can be 0 or 1), so the flag startCount is needed.
• JavaScript numbers are always stored as double precision floating point numbers

number.toString(radix);
parseInt(string, radix);